Determine the magnetic field at the centre of the current carrying wire arrangement shown in the figure. The arrangement extends to infinity. (The wires joining the successive squares are along the line passing through the centre)
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a
μ0i2πa
b
0
c
22μ0iπa ln 2
d
none of these
answer is C.
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Detailed Solution
Magnetic field at centre due to a square of side A:B=4 μ04π ia/2 sin 450 + sin 45022μ0iπaFor the case in figure:Bnet= 22μ0iπ 1a − 12a + 13a − 14a+..... = 22μ0iπa 1 − 12 + 13 − 14+..... = 22μ0iπa ln 2