Questions
A deuteron of kinetic energy 50 keV is describing a circular orbit of radius 0.5 metre in a plane perpendicular to magnetic field . The kinetic energy of the proton that describes a circular orbit of radius 0.5 metre in the same plane with the same , is
detailed solution
Correct option is D
r=2mKqB ⇒K ∝ q2m⇒KpKd = qpqd2 × mdmp = 112 × 21=21⇒ Kp=2 × 50 = 100 keVTalk to our academic expert!
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A charged beam consisting of electrons and positrons enter into a region of uniform magnetic field B perpendicular to field, with a speed v. The maximum separation between an electron and a positron will be (mass of electron = mass of positron = m)
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