For a Deuteron and α-particle the binding energies per nucleon are x and y respectively. Then in the reaction H1 2+H1 2→He2 4+Energy released. Find the energy released.
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a
2(y-x)
b
(4y-2x)
c
4(y-x)
d
2(y+x)
answer is C.
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Detailed Solution
Energy released Q = Final total binding energy - Initial total binding energyQ = 4y - 2 x 2x = 4(y-x)
For a Deuteron and α-particle the binding energies per nucleon are x and y respectively. Then in the reaction H1 2+H1 2→He2 4+Energy released. Find the energy released.