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Q.

In the diagram shown, ABCG and DEFC are square loops of sides 10 cm and 5 cm respectively. A current of 2A is flowing through the wire as shown. A magnetic field of induction B = 0.5 Tesla, parallel to the plane of the composite loop is switched on. Then the resultant magnetic torque experienced by the composite loop is

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a

1.25×10−3N−m

b

0.75 N−m

c

5.5 ×10−4 N−m

d

7.5 ×10−3 N−m

answer is D.

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Detailed Solution

Net magnetic dipole moment of the composite loop is M=[(0.1)2×2−(0.05)2×2]A−m2=0.015 A−m2∴ τ=MBsin⁡90o=0.015×0.5 N−m=7.5×10−3N−m

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