In the diagram shown, E→ is the electric field at a point P on the Gaussian surface,d A→ is the elementary area vector of P. Net flux over the Gaussiansurface is φE=E→.dA→. Then
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a
E→ is produced by +φ1 and -φ2
b
E→ is produced by +φ1,-φ2 and +φ3.
c
φ3=φ1-φ2+φ3E0
d
both (2) and (3) are right.
answer is B.
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Detailed Solution
In the expression φE=E→.A→,the field E→ is the resultant electric field produced by +Q1,-Q2 and +Q3.φE=QnetEo=Q1+Q2Eo.
In the diagram shown, E→ is the electric field at a point P on the Gaussian surface,d A→ is the elementary area vector of P. Net flux over the Gaussiansurface is φE=E→.dA→. Then