Questions
In the diagram shown in figure, match the following columns (Take, g = 10 ms-2)
Column I (A) Normal reaction (8) Force of friction (C) Acceleration of block | Column II (p) 12 SI unit (q) 20 SI unit (r ) zero (s) 2 SI unit |
detailed solution
Correct option is C
N=mg-202sin45°=20 N,f=μkN=12 NSince, 202cos45°>μN block will move and its acceleration will bea=202cos45°-μkNm=20-124=2 ms-2Hence, A→q,B→p,C→s.Talk to our academic expert!
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An ice cube is kept on an inclined plane of angle 30°. The coefficient of kinetic friction between the block and incline plane is the . What is the acceleration of the block?
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