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Q.

In the diagram shown in figure, match the following columns (Take, g = 10 ms-2)Column I(A) Normal reaction(8) Force of friction(C) Acceleration of blockColumn II(p)  12 SI unit(q) 20 SI unit(r ) zero(s) 2 SI unit

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a

A B Cp q r

b

A B Cq p r

c

A B Cq p s

d

A B Cp s r

answer is C.

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Detailed Solution

N=mg-202sin45°=20 N,f=μkN=12 NSince,  202cos45°>μN  block will move and its acceleration will bea=202cos45°-μkNm=20-124=2 ms-2Hence,   A→q,B→p,C→s.
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