Questions

In the diagram shown, the pulley is very light. The particles are released from rest. When the heavier particle falls through a distance of 0.6 m, speed of the particles is

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4 m/s

3 m/s

1 m/s

2 m/s

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detailed solution

Correct option is D

ΔK+ΔU=0⇒12.2m.V2+12.m.V2+mgh+−2m.g.h=0⇒V=2gh3=2×10×0.63 m/s=2 m/s

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