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Q.

In the diagram shown the table top is rough and coefficient of friction between any of the blocks and table top is μ. The blocks A and B are on the verge of slipping. If position of the blocks A and B are interchanged and the system is released from rest, then acceleration of the blocks is

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a

g(1−μ)(1+μ)

b

μg

c

g(1+μ)

d

g(1−μ)

answer is D.

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Detailed Solution

In the first case, mg=μ×Mg⇒m=μMIn the second case, resultant driving force on the blocks =Mg−μmg=Mg(1−μ2)∴ Acceleration, a=Mg(1−μ2)(M+m)=Mg(1−μ2)M(1+μ)=g(1−μ)
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