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In the diagram shown, a wire carries current I. The loop has N turns and part of helical loop on which arrows are drawn is outside the plane of paper. What is the value of the B.dl ( as in Ampere's law) on the helical loop shown in the figure?

a
−μ0NI
b
μ0I
c
μ0NI
d
Zero

detailed solution

Correct option is C

Here B→ (due to I) and dl→ will be in same direction.So, ∮B→. dl→ = ∮B dl cos 00∮B dl = ∮B dl=B N 2πr =NB2πr=Nμ0I

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