Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The diagram shows a circular non-conducting smooth fixed track kept concentric to a magnetic field of magnitude B which exists in a cylindrical region of radius r (r > R). There is small bead of mass m and charge q rests on the track. A bead can move freely along track. If the magnetic field is switched off then

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

Impulse imparted to bead is qRB2

b

Impulse imparted to bead is qRB

c

If q=4mBgR then bead will complete vertical circular motion

d

If  q=mBgRthen bead will complete vertical circular motion

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Sudden removal of magnetic field results in induced emf, which produces non conservative eletric field.This electric field applies impulsive force on charge.∮E→ .dr→=ξ=−dϕdt⇒E2πR=πR2dBdt⇒Edt=RdB2⇒ Impulse =∫Fdt=∫qEdt=∫qR2dB=qRB2​⇒mv=qRB2⇒ Minimum velocity to complete a circle =4gR​⇒q=2mvRB=2mRB4gR=4mBgR
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring