The diagram shows a solenoid carrying time varying current l = l0t. On the axis of the solenoid, a ring has been placed. The mutual inductance of the ring and the solenoid is M and the self-inductance of the ring is L. If the resistance of the ring is R then maximum current which can flow through the ring is

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(2M+L)l0R

MI0R

(2M−L)I0R

(M+L)I0R

answer is B.

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Detailed Solution

ϕ=MI=MI0t Hence, induced emf ε=dϕdt=MI0 Current through ring =εR=MI0R

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