The diagram shows a solenoid carrying time varying current l = l0t. On the axis of the solenoid, a ring has been placed. The mutual inductance of the ring and the solenoid is M and the self-inductance of the ring is L. If the resistance of the ring is R then maximum current which can flow through the ring is
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a
(2M+L)l0R
b
MI0R
c
(2M−L)I0R
d
(M+L)I0R
answer is B.
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Detailed Solution
ϕ=MI=MI0t Hence, induced emf ε=dϕdt=MI0 Current through ring =εR=MI0R