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Q.

The diameter of a brass rod is 4 mm and Young's modulus of brass is  9×1010 N/m2. The force required to stretch by 0.1% of its length is

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a

360 πN

b

36 N

c

144π×103N

d

36π×105N

answer is A.

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Detailed Solution

F=YAlL=9×1010×π×4×10−6×0.1100=360 π N
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