The diameter of a cylinder is measured using a Vernier calipers with no zero error. If is found that the zero of the Vernier scale lies between 5.10cm and 5.15cm of the main scale. The Vernier scale has 50 divisions equivalent to 2.45cm. The 24division of the Vernier scale exactly coincides with one of the main scale divisions. The diameter of cylinder is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
5.112cm
b
5.124cm
c
5.136cm
d
5.148cm
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
value of 1 Vernier Scale Division= 1 VSD=2.45cm50=0.049cm value of 1 Main Scale Division=1MSD =5.15−5.10=0.05cm Least Count=L.C = value of 1MSD −value of1VSD =0.05−0.049 =0.001cm given Vernier Coincidence= VC=24 Diameter of wire =MSD+VC×L.C =5.10+24×0.001 =5.10+0.024 Diameter of wire =5.124cm
The diameter of a cylinder is measured using a Vernier calipers with no zero error. If is found that the zero of the Vernier scale lies between 5.10cm and 5.15cm of the main scale. The Vernier scale has 50 divisions equivalent to 2.45cm. The 24division of the Vernier scale exactly coincides with one of the main scale divisions. The diameter of cylinder is