First slide

Measurement

Question

The diameter of a cylinder is measured using a vernier callipers with no zero error. It is found that the zero of the vernier scale lies between $5.10 cm$ and $5.15 cm$ of the main scale. The vernier scale has 50 division equivalent to $2.45 cm$ . The 24 th division of the vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is

Moderate

A

5.112 cm
B

5.124 cm
C

5.136 cm
D

5.148 cm

Solution

$1 MSD = 5.15 cm - 5.10 cm = 0.05 cm$
$1 VSD = \frac{2.45 cm}{50} = 0.049 cm$
$L C = 1 M S D - 1 V S D$
$= 0.001 cm$
Hence, diameter of cylinder =( Main scale reading ) + Vemier scale reading)(LC)
$= 5.10 + (24) (0.001)$
$= 5.124 cm$

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