The diameter of a cylinder is measured using a vernier callipers with no zero error. It is found that the zero of the vernier scale lies between $$5.10$$ cm and $$5.15$$ cm of the main scale. The vernier scale has $$50$$ division equivalent to $$2.45$$ cm. The $$24$$ th division of the vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is

Question

The diameter of a cylinder is measured using a vernier callipers with no zero error. It is found that the zero of the vernier scale lies between $$5.10$$ cm and $$5.15$$ cm of the main scale. The vernier scale has $$50$$ division equivalent to $$2.45$$ cm. The $$24$$ th division of the vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is

Infinity Learn · Accepted Answer

$$1MSD=5.15$$ $$cm-5.10$$ $$cm=0.05$$ $$cm1VSD=2.45$$ $$cm50=0.049$$ cmL $$C=1$$ M S $$D-1$$ V S $$D=0.001$$ cmHence, diameter of cylinder $$=($$ Main scale reading $$)$$ $$+$$ Vemier scale $$reading)(LC)=5.10+(24)(0.001)=5.124$$ cm

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