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Q.

The diameter of the moon is 3.5  × 103  km and its distance from earth is 3.8  × 105  km. When seen by a telescope having focal lengths of the objective and the eye piece as 40 mm and 10 mm respectively, the angle subtended by the image of the moon at the eyes for normal vision will be approximately

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a

20

b

100

c

40

d

200

answer is A.

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Detailed Solution

(1)Angular magnification = βα=f0feNow  α  =  3.5  ×  1033.8  ×  105rad=9.210  ×  10−3rad.∴   β  =9.210   ×  10−3  ×  4010  rad  ≃ 20
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