The diameter of a wire is measured by a screw gauge and found to be 1.004cm, 1.000cm, 1.008cm. The absolute error in the second reading is

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0.002 cm

0.004 cm

0.006 cm

0.003 cm

answer is B.

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Detailed Solution

amean = 1.004+1.000+1.0083=1.0123=1.004cm |Δa2|=|a2−amean|=|1−1.004|=0.004cm

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