The diameter of a wire stretched by a force of 144 N between two bridges distant 50 cm is 1 mm. It produces 4 beats with a tuning fork while vibrating in fundamental mode. On reducing the tension to 121 N, again 4 beats/sec are heard. The frequency of fork is
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a
75 Hz
b
85 Hz
c
195 Hz
d
92 Hz
answer is D.
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Detailed Solution
we know that n∝TLet the frequency of fork be n. Thenn1−n=4 or n1=n+4 and n−n2=4 or n2=n−4 n1n2=n+4n−4 From eqs. (1) and (2) 1211=n+4n−4 n=92Hz
The diameter of a wire stretched by a force of 144 N between two bridges distant 50 cm is 1 mm. It produces 4 beats with a tuning fork while vibrating in fundamental mode. On reducing the tension to 121 N, again 4 beats/sec are heard. The frequency of fork is