A diatomic molecule is formed by two atoms which may be treated as mass points m1 and m2,joined by a massless rod of length r. Then the moment of inertia of the molecule about an axis passing through the centre of mass and perpendicular to rod is

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m1+m2r2

m1+m2m1m2r2

m1m2m1+m2r2

answer is D.

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Detailed Solution

The moment of inertia about centre of massI=m1x2+m2(r−x)2The moments of masses about centre of massm1X=m2(r−X)or x=m2m1+m2r∴ I=m1m2rm1+m22+m2m1rm1+m22=m1m2m+m2r2

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