Questions
A diatomic molecule is formed by two atoms which may be treated as mass points m1 and m2,joined by a massless rod of length r. Then the moment of inertia of the molecule about an axis passing through the centre of mass and perpendicular to rod is
detailed solution
Correct option is D
The moment of inertia about centre of massI=m1x2+m2(r−x)2The moments of masses about centre of massm1X=m2(r−X)or x=m2m1+m2r∴ I=m1m2rm1+m22+m2m1rm1+m22=m1m2m+m2r2Talk to our academic expert!
Similar Questions
Three point masses, each of m, are placed at the corners of an equilateral triangle of side l. Then the moment of inertia of this system about an axis along one side of the triangle is
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