Questions
The dielectric strength of air at NTP is then the maximum charge that can be given to a spherical conductor of radius 3 m is
detailed solution
Correct option is B
By using E=9×109×QR2⇒3×106=9×109×Q(3)2⇒Q=3×10−3CTalk to our academic expert!
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Equal charges q are placed at the vertices A and B of an equilateral triangle ABC of side a. The magnitude of electric field at the point C is
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