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Q.

The difference between the apparent frequencies of a source of sound as perceived by a stationary observer during its approach and recession is 2% of the actual frequency of the source. If the speed of sound is 300 m/s, the speed of source is

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a

1.5 m/s

b

3 m/s

c

6 m/s

d

12 m/s

answer is B.

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Detailed Solution

fapproach-frecedef=∆ff=vv-vs-vv+vs ∴ ∆ff=v(v+vs-v+vs)v2-vs2=2vvsv2-vs2 But ∆ff=×100=2% ⇒ 0.02=2(300)vs(300)2-vs2 ⇒ 0.02=2(300)vs(300)2=2300vs vs=(0.01)300=3 m/s

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