Q.
In a diffraction pattern due to a single slit of width a , the first minimum is observed at an angle 300when light of wavelength 5000Å is incident on the slit. The first secondary maximum is observed at an angle of
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a
sin-112
b
sin-134
c
sin-114
d
sin-123
answer is B.
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Detailed Solution
For first minimum, the path difference between extreme waves, asinθ=λ Here θ=30°⇒sinθ=12 ∴a=2λ..........(1)For first secondary maximum, the path difference between extreme wavesasinθ'=32λ or (2λ)sinθ'=32λ [Using eqn (i)] or sinθ'=34 ∴ θ'=sin-134
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