In the diffraction pattern of single slit under bichromatic illumination, the first minimum with the wavelength${\lambda }_1$is found to be coincident with the third maximum at ${\lambda }_2$. So

• A

  $3{\lambda }_1=0.3{\lambda }_2$

• B

  $3{\lambda }_1={\lambda }_2$

• C

  ${\lambda }_1 =3.5{\lambda }_2$

• D

  $0.3{\lambda }_1=3{\lambda }_2$