In the diffraction pattern of single slit under bichromatic illumination, the first minimum with the wavelengthλ1is found to be coincident with the third maximum at λ2. So
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a
3λ1=0.3λ2
b
3λ1=λ2
c
λ1 =3.5λ2
d
0.3λ1=3λ2
answer is C.
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Detailed Solution
first minima of λ1 Sinθ1=λ1/d third maxima of λ2 Sinθ3 = 7λ22d λ1d=7λ22d λ1 =3.5 λ2