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Questions  

The dimension of ab in the equation P=a-t2bx, where P is pressure, x is distance and t is time, is 

a
MT−2
b
M2LT−3
c
ML3T−1
d
LT−3

detailed solution

Correct option is A

[a]=T2 and [b]=a−t2[P][x]=T2ML−1T−2[L]⇒ [b]=M−1T4 So  ab=T2M−1T4=MT−2

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