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Q.

The dimension of ab in the equation P=a-t2bx, where P is pressure, x is distance and t is time, is

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a

MT−2

b

M2LT−3

c

ML3T−1

d

LT−3

answer is A.

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Detailed Solution

[a]=T2 and [b]=a−t2[P][x]=T2ML−1T−2[L]⇒ [b]=M−1T4 So  ab=T2M−1T4=MT−2
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