In dimension of critical velocity vc, of liquid following through a tube are expressed as (ηxρyrz), where η, ρ and r are the coefficients of viscosity of liquid, density of liquid and radius of the tube respectively, then the values of x, y and z are given by
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a
1, 1, 1
b
1, -1, -1
c
-1, -1, 1
d
-1,-1, -1
answer is B.
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Detailed Solution
Vc = [ηxρyrz][L1T-1]∝ [M1L-1T-1]x[M1L-3]y[L1]z [L1T-1] ∝ [Mx+y][L-x-3y+z][T-x]taking comparison on both sides,x+y = 0, -x-3y+z = 1, -x = -1⇒x =1, y = -1, z = -1