The dimension of e2/4πε0hc, where e,ε0, h and c are electric charge, electric permittivity of free space, Planck's constant and velocity of light in vacuum, respectively, is
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a
M0L0T0
b
M1L0T0
c
M0L1T0
d
M0L0T1
answer is A.
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Detailed Solution
[e]=[AT] , ε0=M−1L−3T4A2 , [h]=ML2T−1 and [c]=LT−1e24π∈0hc=A2T2M−1L−3T4A2×ML2T−1×LT−1=M0L0T0To calculate ∈0, we can use the formula F=q1q24πε0r2
The dimension of e2/4πε0hc, where e,ε0, h and c are electric charge, electric permittivity of free space, Planck's constant and velocity of light in vacuum, respectively, is