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The dimension of (1/2) $ε_{0} E^{2} (ε_{0}$ : permittivity of free space; E : electric field) is

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MLT −1

ML2T−2

ML−1T−2

ML2T−1

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detailed solution

Correct option is C

Energy density = EnergyVolume so it’s dimensions are ML2T−2L3=[ML−1T−2]

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The dimension of (1/2) ε0E2 ε0 : permittivity of free space; E : electric field) is

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The dimension of (1/2) $ε_{0} E^{2} (ε_{0}$ : permittivity of free space; E : electric field) is