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Questions  

The dimension of (1/2) ε0E2ε0:permittivity of free space; E: electric field) is

a
[MLT-1]
b
[ML2T2]
c
[ML-1T-2]
d
[ML2T-2]

detailed solution

Correct option is C

Energy density = Energy  Volume , so its dimensions are  ML2 T-2L3=ML-1 T-2

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