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The dimension of $\frac{1}{2} ε_{0} E^{2}$ ( $ε_{0}$ : permittivity of free space; E: electric field) is

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MLT−1

ML2T−2

ML−1T−2

ML2T−1

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detailed solution

Correct option is C

Energy density=EnergyVolumeSo it’s dimensions areML2T−2L3=ML−1T−2

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The dimension of 12 ε0E2(ε0: permittivity of free space; E: electric field) is

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The dimension of $\frac{1}{2} ε_{0} E^{2}$ ( $ε_{0}$ : permittivity of free space; E: electric field) is