The dimension of stopping potential $V_0$  in photoelectric effect in units of Planck’s constant ‘h’, speed of light ‘C’ and universal gravitational constant ‘G’ and ampere A is:

detailed solution

Correct option is B

V=KhaAbGcCd  (V is voltage)We know  h=ML2T−1[A] = A[G] = M-1L3T-2[C] = LT-1[V] =   ML2T-3A−1  comparing dimensions on both sides, ML2T-3A−1  =   ML2T−1aAbM−1L3T−2cLT−1d ⇒ML2T-3A−1  =  Ma−cL2a+3c+dT−a−2c−dAbComparing the powers,  a−c=1..................(1)b=−1.................2−a−2c−d = −3 .........3​2a+3c+d = 2 .............4Add 3 and 4 ,  ​a+c = −1 .........5​​Add 1 and 5 , ​2a =0​⇒a=0​∴c=−1​​Put values of a and c in 3,​2−d=−3​⇒d=5​​Thus, V=K h0A−1G−1C5​