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The dimensional formula of $\frac{1}{2} ε_{0} E^{2}$ ( $ε_{0}$ : permittivity of free space and $E :$ Intensity of electric field) is

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MLT−1

ML2T−1

ML−1T−2

ML2T−2

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Correct option is C

GivenEnergy density of electric field =12ε0E2Here ε0= Permittivity of free spaceE=Intensity of electric field⇒12ε0E2=EnergyVolume=ML2T−2L3=ML−1T−2∴Dimension formula of 12ε0E2=ML−1T−2Therefore, the correct answer is (C).

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The dimensional formula of 12ε0E2 (ε0: permittivity of free space and E: Intensity of electric field) is

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The dimensional formula of $\frac{1}{2} ε_{0} E^{2}$ ( $ε_{0}$ : permittivity of free space and $E :$ Intensity of electric field) is