The dimensional formula of 12ε0E2 (ε0: permittivity of free space and E: Intensity of electric field) is
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a
MLT−1
b
ML2T−1
c
ML−1T−2
d
ML2T−2
answer is C.
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Detailed Solution
GivenEnergy density of electric field =12ε0E2Here ε0= Permittivity of free spaceE=Intensity of electric field⇒12ε0E2=EnergyVolume=ML2T−2L3=ML−1T−2∴Dimension formula of 12ε0E2=ML−1T−2Therefore, the correct answer is (C).