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The dimensions of μ0ε01/2 are

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By Expert Faculty of Sri Chaitanya
a
L1/2T−1/2
b
L−1T
c
LT−1
d
L1/2T1/2
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detailed solution

Correct option is C

The speed of the light in vacuum is c=1μ0ε0=μ0ε0−1/2∴ μ0ε0−1/2=[c]=LT−1


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