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The dimensions of ${(μ_{0} ε_{0})}^{- 1 / 2}$ are

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L1/2T−1/2

L−1T

LT−1

L1/2T1/2

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detailed solution

Correct option is C

The speed of the light in vacuum is c=1μ0ε0=μ0ε0−1/2∴ μ0ε0−1/2=[c]=LT−1

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The dimensions of μ0ε0−1/2 are

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The dimensions of ${(μ_{0} ε_{0})}^{- 1 / 2}$ are