Q.

The dimensions of ab in the equation P = a−t2bx2 where P is pressure, x is distance and t is time, are:

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a

[M2L T–3]

b

[MLT–2]

c

[LT–3]

d

[ML3T-1]

answer is B.

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Detailed Solution

P=a−t2bx2=abx2−t2bx2As per principle of dimensional homogeneity each term in the equation must carry the dimension of pressure.P=abx2⇒ab=Px2=ML−1T−2L2⇒ab=MLT−2
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The dimensions of ab in the equation P = a−t2bx2 where P is pressure, x is distance and t is time, are: