Q.
The dimensions of ab in the equation P = a−t2bx2 where P is pressure, x is distance and t is time, are:
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a
[M2L T–3]
b
[MLT–2]
c
[LT–3]
d
[ML3T-1]
answer is B.
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Detailed Solution
P=a−t2bx2=abx2−t2bx2As per principle of dimensional homogeneity each term in the equation must carry the dimension of pressure.P=abx2⇒ab=Px2=ML−1T−2L2⇒ab=MLT−2
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