Q.

The dimensions of coefficient of thermal conductivity is:

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a

ML2T−2K−1

b

MLT−3K−1

c

MLT −2K−1

d

MLT−3K

answer is B.

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Detailed Solution

dQdt=−KAdθdx⇒[K]=ML2T−2[T]×[L]L2[K]=MLT−3K−1
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The dimensions of coefficient of thermal conductivity is: