Q.
The dimensions of coefficient of thermal conductivity is:
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a
ML2T−2K−1
b
MLT−3K−1
c
MLT −2K−1
d
MLT−3K
answer is B.
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Detailed Solution
dQdt=−KAdθdx⇒[K]=ML2T−2[T]×[L]L2[K]=MLT−3K−1
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