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Q.

A dip circle is adjusted so that its needle moves freely in the magnetic meridian. In this position, the angle of dip is 40o. Now the dip circle is rotated so that the plane in which the needle moves makes an angle of 30o with the magnetic meridian. In this position the needle will dip by an angle

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a

40o

b

30o

c

More than 40o

d

Less than 40o

answer is C.

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Detailed Solution

tanθ=BVBH .........(i)If apparent dip is θ', thentanθ'=B'VB'H=BVBH cos30o=BVBH x 32⇒tanθ'=23 tanθ⇒tanθ'>tanθ⇒θ'>θ⇒θ'>40

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