A dip circle lies initially in the magnetic meridian. If it is now rotated through angle θ in the horizontal plane, then tangent of the angle of dip is changed in the ratio
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a
1 : cos θ
b
cos θ : 1
c
1 : sin θ
d
sin θ : 1
answer is A.
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Detailed Solution
Here, tanδ=BVBH and tanδ'=BVBH cos θ∴tan δ'tan δ=BVBH cos θ x BHBV =1cos θ