First slide

Earth's Magnetism

Question

A Dip circle lying initially in the magnetic meridian, the angle of dip is 45^o. Now dip circle is rotated through 30^o in the horizontal plane. The apparent angle of dip is

Moderate

A

${Tan}^{- 1} \frac{2}{\sqrt{3}}$
B

${Tan}^{- 1} \frac{\sqrt{3}}{2}$
C

${Tan}^{- 1} 2$
D

${Tan}^{- 1} \frac{1}{2}$

Solution

$\begin{array}{rcl} \tan δ_{1} & = & \frac{tanδ}{cosθ} = \frac{\tan 45}{\cos 30} = \frac{1 x 2}{\sqrt{3}} \\ δ_{1} & = & \tan^{- 1} (\frac{2}{\sqrt{3}}) \end{array}$

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