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Q.

A dip needle lies initially in the magnetic meridian when it shows an angle of dip 'θ' at the place. The dip circle is rotated through an angle 'x' in the horizontal plane and then it shows an angle of dip θ1. Then, tanθ1/tanθ is

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a

1/cosx

b

1/sinx

c

1/tanx

d

cosx

answer is A.

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Detailed Solution

As the dip circle is rotated , we have to take the component of BHInitially , tanθ=BvBHFinally , tanθ1=BvBHcosx Dividing , we get tanθtanθ1=Bv/BHBv/BHcosx⇒tanθtanθ1=cosx⇒tanθ1tanθ=1cosx

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