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The dipole moment of a short bar magnet is 1.25 Am2. The magnetic field on its axis at a distance of 0.5 metre from the centre of the magnet is 

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1.0 x 10-4 N/Am
4 x 10-2 N/Am
2 x 10-6 N/Am
6.64 x 10-8 N/Am

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detailed solution

Correct option is C

B=μ04π2Md3=10-7 x 2 x 1.250.53=2 x 10-6 N/A-m

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