The dipole moment of a short bar magnet is 1.25 A-m2. The magnetic field on its axis at a distance of 0.5metre from the centre of the magnet is

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1.0×10−4Newton/amp−meter

4×10−2Newton/amp−metre

2×10−6Newton/amp−metre

6.64×10−8Newton/amp−metre

answer is C.

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Detailed Solution

B=μ04π2Md3=10−7×2×1.250.53=2×10−6N/A−m

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