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The direction cosines of $\bar{A}$ are $\cos α = \frac{4}{5 \sqrt{2}}, \cos β = \frac{1}{\sqrt{2}}$ and $\cos γ = \frac{3}{5 \sqrt{2}}$ then the vector A is

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Correct option is B

cosα=452,cosβ=552, cosγ=352 ∴A¯=4i+5j+3k

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The direction cosines of A¯ are cosα=452,cosβ=12 and cosγ=352 then the vector A is

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The direction cosines of $\bar{A}$ are $\cos α = \frac{4}{5 \sqrt{2}}, \cos β = \frac{1}{\sqrt{2}}$ and $\cos γ = \frac{3}{5 \sqrt{2}}$ then the vector A is