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The direction cosines of a vector $\large \vec A$ of magnitude 5√2 are $\large \cos \alpha = \frac{4}{{5\sqrt 2 }}$ , $\large \cos \beta = \frac{1}{{\sqrt 2 }}$ and $\large \cos \gamma = \frac{3}{{5\sqrt 2 }}$ then the vector $\large \vec A$ is

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The direction cosines of a vector of magnitude 5√2 are , and then the vector is

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The direction cosines of a vector $\large \vec A$ of magnitude 5√2 are $\large \cos \alpha = \frac{4}{{5\sqrt 2 }}$ , $\large \cos \beta = \frac{1}{{\sqrt 2 }}$ and $\large \cos \gamma = \frac{3}{{5\sqrt 2 }}$ then the vector $\large \vec A$ is