The direction of magnetic force on the electron as shown in the diagram is along,
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a
Y-axis
b
–Y –axis
c
Z-axis
d
–Z –axis
answer is A.
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Detailed Solution
In figure, magnetic field direction due to current carrying wire is along −k^ into the page.So, magnetic force, F→=qV→ X B→ F→=(−e)(−Vi^)X(−Bk^)=−eVi^ X Bk^=−e(V X B)(i^ X k^)=−e(VB)(−j^)=e(VB)j^