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Torque
Question

A disc of mass 4 kg and radius 50 cm is rotating with angular velocity 30 rad/s about a spindle passing through its centre and perpendicular to the plane of the disc. A constant braking torque is applied on the disc and the disc stops spinning in 10 second. Then the magnitude of the braking torque is

Easy
Solution

Moment of inertia I=12×4×0.52Kgm2=0.5kgm2

using ω=ω0αt0=30α×10α=3rad/s2

 Braking torque τ=Iα=0.5×3Nm=1.5Nm

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