Questions
A disc of mass 4 kg and radius 50 cm is rotating with angular velocity 30 rad/s about a spindle passing through its centre and perpendicular to the plane of the disc. A constant braking torque is applied on the disc and the disc stops spinning in 10 second. Then the magnitude of the braking torque is
detailed solution
Correct option is C
Moment of inertia I=12×4×0.52Kg−m2=0.5 kg−m2using ω=ω0−αt⇒0=30−α×10⇒α=3 rad/s2∴ Braking torque τ=Iα=0.5×3 N−m=1.5 N−mTalk to our academic expert!
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A disc can rotate about an axis passing through its centre and perpendicular to the plane of the disc. Initially the disc is stationary and its moment of inertia about the axis is 4 Kg-m2. A torque is applied on the disc which varies with time according to the graph shown in figure. Then angular velocity of the disc at the end of 6th second is
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