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Q.

A disc of mass m and radius R is rolling without slipping on a horizontal plane with angular velocity ω. P is a point in space in the plane of the disc at a height 2R above the horizontal plane. Then angular momentum of the disc about point P is

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a

14ωm R2

b

ωm R2

c

2ωm R2

d

12ωm R2

answer is D.

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Detailed Solution

L→P=L→comP +  ICω→LP=mVcR−IC.ω=mωRR−12  mR2ω=12mωR2
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