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A disc of mass m and radius R is rolling without slipping on a horizontal plane with angular velocity ω. P is a point in space in the plane of the disc at a height 2R above the horizontal plane. Then angular momentum of the disc about point P is

a
14ωm R2
b
ωm R2
c
2ωm R2
d
12ωm R2

detailed solution

Correct option is D

L→P=L→comP +  ICω→LP=mVcR−IC.ω=mωRR−12  mR2ω=12mωR2

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