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Q.

A disc of mass M and radius R rolls without slipping on a horizontal surface. If the velocity of its center is v0, then the total angular momentum of the disc about a fixed point P at a height (3/2)R above the center C

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a

increases continuously as the disc moves away

b

decreases continuously as the disc moves away

c

is equal to 2MRv0

d

is equal to MRv0

answer is D.

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Detailed Solution

L→=ICMω→+mr→×v→CM=MR22ω(−k^)+M32R(−j^)×v0i^=MRv0k^
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