A disc of mass M and radius R rolls without slipping on a horizontal surface. If the velocity of its center is $$v0$$, then the total angular momentum of the disc about a fixed point P at a height $$(3/2)R$$ above the center C

Correct option is 4is equal to MRv0

Questions

A disc of mass M and radius R rolls without slipping on a horizontal surface. If the velocity of its center is v₀, then the total angular momentum of the disc about a fixed point P at a height (3/2)R above the center C

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increases continuously as the disc moves away

decreases continuously as the disc moves away

is equal to 2MRv0

is equal to MRv0

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detailed solution

Correct option is D

L→=ICMω→+mr→×v→CM=MR22ω(−k^)+M32R(−j^)×v0i^=MRv0k^

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A disc of mass M and radius R rolls without slipping on a horizontal surface. If the velocity of its center is v0, then the total angular momentum of the disc about a fixed point P at a height (3/2)R above the center C

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A disc of mass M and radius R rolls without slipping on a horizontal surface. If the velocity of its center is v₀, then the total angular momentum of the disc about a fixed point P at a height (3/2)R above the center C