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Questions  

A disc is rolling (without slipping) on a horizontal surface. C is its centre and Q and P are two points equidistant from C. Let vp,vQ. and vC be the 

magnitudes of velocities of points, P, Q and C respectively, then

a
VQ>VC>VP
b
vQ
c
vQ=vP,vC=12cP
d
vQvP

detailed solution

Correct option is A

If O be the point of contact of the disc with the surface , then at any instant of time the disc is rotating about point o and O is called the instantaneous centre of rotation . Velocity of any point on the disc at a radial distance r from O is given by V = ωr.OQFrom fig. OQ > AC > OPWe know that V=rω∴ vQ>vC>vP

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Similar Questions

I. Speed of any point on rigid body executing rolling motion can be calculated by the expression ν=rω
where r is the distance of point from instantaneous centre of rotation.
II. Rolling motion of rigid body can be considered as a pure rotation about instantaneous centre of rotation.
Which of the above statement{s} is/are correct? 


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