Questions
A disc rotates freely with rotational kinetic energy E about a normal axis through centre. A ring having the same radius but double the mass of disc is now, gently placed on the disc. The new rotational kinetic energy of the system would be
detailed solution
Correct option is B
E=L22I here l=constant so E1E2=I2I1 initial moment of inertia=MR22 final moment of inertia MR22+2MR2=5MR22 E2=E5Talk to our academic expert!
Similar Questions
Two discs of same moment of inertia rotating about their regular axis passing through centre and
perpendicular to the plane of disc with angular velocities and . They are brought into contact
face to face coinciding the axis of rotation. The expression for loss of energy during this process is
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