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Q.

A disc rotates freely with rotational kinetic energy E about a normal axis through centre. A  ring having the same radius but double the mass  of disc is now, gently placed on the disc. The  new rotational kinetic energy of the system  would be

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a

E2

b

E5

c

2E5

d

E3

answer is B.

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Detailed Solution

E=L22I  here l=constant so E1E2=I2I1 initial moment of inertia=MR22 final moment of inertia MR22+2MR2=5MR22 E2=E5
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