Q.

A disc shaped body (having a semi circular hole as shown in the figure) of mass m=10 kg  and  radius   R=109m  is  performing  pure  rolling motion on  a  rough  horizontal  surface.  In the figure  point  O  is  geometrical center  of  the  disc  and  at  this  instant  the  center  of  mass  C  of  the disc is at same horizontal level with O. The radius of gyration of the disc  about  an  axis  passing    through  C  and  perpendicular  to  the  plane of the disc is  R2 and at the instant shown the angular velocity of  the  disc  is  ω=gR rad/sec   in  clockwise  sense.  g  is  acceleration due to gravity = 10 m/s2 .  Find angular acceleration α  (in rad/  s2) of the disc at this instant.

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answer is 6.

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Detailed Solution

Considering torque of real and pseudo force in the frame of P bottom point,τ=mgR2+mω2RR2​⇒τ=mgR2+mgRRR2=mgR​Moment of Inertia about P, IP=IC+m(CP)2=m(R2)2+m(R2+R24)=32mR2​∴   α=τI=2mgR3mR2=2g3R=6  rad/s2
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