Q.
A disc shaped body (having a semi circular hole as shown in the figure) of mass m=10 kg and radius R=109m is performing pure rolling motion on a rough horizontal surface. In the figure point O is geometrical center of the disc and at this instant the center of mass C of the disc is at same horizontal level with O. The radius of gyration of the disc about an axis passing through C and perpendicular to the plane of the disc is R2 and at the instant shown the angular velocity of the disc is ω=gR rad/sec in clockwise sense. g is acceleration due to gravity = 10 m/s2 . Find angular acceleration α (in rad/ s2) of the disc at this instant.
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answer is 6.
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Detailed Solution
Considering torque of real and pseudo force in the frame of P bottom point,τ=mgR2+mω2RR2⇒τ=mgR2+mgRRR2=mgRMoment of Inertia about P, IP=IC+m(CP)2=m(R2)2+m(R2+R24)=32mR2∴ α=τI=2mgR3mR2=2g3R=6 rad/s2
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