In a discharge tube when 200 V potential difference is applied 6.25 x 1018 electrons move from cathode to anode and 3.125 x 1018 singly charged positive ions move from anode to cathode in one second. Then the power of, tube (in W) is ________.
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answer is 300.
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Detailed Solution
We use P=Vi=Vqt=2006.25×1018+3.125×1018×1.6×10−191=300watt