Q.
A disk with moment of inertia I1 rotates about a frictionless, vertical a:de with angular speed ω1. A second disk, this one having moment of inertia l2 and initially not rotating, drops onto the first disk (figure). Because of friction between the surfaces, the two eventually reach the same angular speed ωf The value of ωf is
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a
I1+I2I1ωi
b
I1I1+I2ωi
c
I1+I2I2ωi
d
I1I2ωi
answer is B.
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Detailed Solution
From conservation of angular momentum for the isolated system of two disks:I1+I2ωf=I1ωi or ωf=I1I1+I2ωi
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